| View previous topic :: View next topic |
| Author |
Message |
amy666
Guest
|
 Posted: Sat Jul 12, 2008 8:07 pm Post subject: a^b + c^d + e^f = b^a + d^c + f^e ( number theory ) |
 |
|
let all variables be distinct integers >= 2.
a^b + c^d + e^f = b^a + d^c + f^e
does a solution exist ?
regards
tommy1729 |
|
| Back to top |
|
 |
| |
Ads |
Advertising
Sponsor
|
|
joe
Guest
|
| Posted: Sun Jul 13, 2008 3:33 am Post subject: Re: a^b + c^d + e^f = b^a + d^c + f^e ( number theory ) |
|
|
"amy666" <tommy1729@hotmail.com> wrote:
| Quote: |
let all variables be distinct integers >= 2.
a^b + c^d + e^f = b^a + d^c + f^e
does a solution exist ?
|
It seems to be true for v >= 17.
Tested only upto v=120 using combination sets of size k=6. |
|
| Back to top |
|
|
| |
Ads |
Advertising
Sponsor
|
|
joe
Guest
|
| Posted: Sun Jul 13, 2008 3:43 am Post subject: Re: a^b + c^d + e^f = b^a + d^c + f^e ( number theory ) |
|
|
"joe" <joe@iamnotathome.org.invalid> wrote:
| Quote: |
"amy666" <tommy1729@hotmail.com> wrote:
let all variables be distinct integers >= 2.
a^b + c^d + e^f = b^a + d^c + f^e
does a solution exist ?
It seems to be true for v >= 17.
Tested only upto v=120 using combination sets of size k=6.
|
Oops, I overlooked to condition >=2.
Hmm. then I dunno if a sol exists. |
|
| Back to top |
|
|
| |
Ads |
Advertising
Sponsor
|
|
|
FAQ
Search
Memberlist
Usergroups
Register
Profile
Log in to check your private messages
Log in
