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China -->hk
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 Posted: Thu May 24, 2007 6:48 am Post subject: hi,friends(3) |
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hi,friends,
can you help me: how do we get cos[2*Pi/7]+cos[4*Pi/7]?
thanks, |
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José Carlos Santos
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| Posted: Thu May 24, 2007 11:03 am Post subject: Re: hi,friends(3) |
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On 24-05-2007 7:48, China -->hk wrote:
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can you help me: how do we get cos[2*Pi/7]+cos[4*Pi/7]?
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What do you mean? It doesn't look like it is possible to simplify that
expression. Numerically, the value is about 0.40097.
Best regards,
Jose Carlos Santos |
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China -->hk
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| Posted: Sat May 26, 2007 7:30 am Post subject: Re: hi,friends(3) |
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hi:
surely I mean for simplification.As we know: cos[Pi/7]-cos[2*Pi/7]+cos[3*Pi/7] can simplified as 1/2.
anyway,thanks to you all. |
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